# help

• Nov 13th 2013, 05:30 AM
vegasgunner
help
• Nov 13th 2013, 05:35 AM
SlipEternal
Re: help
In the second equation, solve for \$\displaystyle \dfrac{1}{p}\$.

First \$\displaystyle q = \dfrac{9}{2p}\$. Then, multiply both sides by \$\displaystyle \dfrac{2}{9}\$. So, \$\displaystyle \dfrac{2q}{9} = \dfrac{1}{p}\$. Then \$\displaystyle \dfrac{2q}{9} + \dfrac{1}{q} = 1\$. Now, solve for \$\displaystyle q\$.
• Nov 13th 2013, 05:42 AM
SlipEternal
Re: help
Note: There are a number of ways to solve the system of equations. You first need an expression for \$\displaystyle p\$ in terms of \$\displaystyle q\$, so in the first equation, you could multiply both sides by \$\displaystyle pq\$. Then \$\displaystyle q+p = pq\$. Now, solve for \$\displaystyle p\$:

\$\displaystyle p-pq = -q\$

\$\displaystyle p(1-q) = -q\$

\$\displaystyle p = \dfrac{-q}{1-q} = \dfrac{q}{q-1}\$

Plug that into the second equation and solve for \$\displaystyle q\$.
• Nov 13th 2013, 05:46 AM
vegasgunner
Re: help
thank you I solved it