# help

• November 13th 2013, 05:30 AM
vegasgunner
help
• November 13th 2013, 05:35 AM
SlipEternal
Re: help
In the second equation, solve for $\dfrac{1}{p}$.

First $q = \dfrac{9}{2p}$. Then, multiply both sides by $\dfrac{2}{9}$. So, $\dfrac{2q}{9} = \dfrac{1}{p}$. Then $\dfrac{2q}{9} + \dfrac{1}{q} = 1$. Now, solve for $q$.
• November 13th 2013, 05:42 AM
SlipEternal
Re: help
Note: There are a number of ways to solve the system of equations. You first need an expression for $p$ in terms of $q$, so in the first equation, you could multiply both sides by $pq$. Then $q+p = pq$. Now, solve for $p$:

$p-pq = -q$

$p(1-q) = -q$

$p = \dfrac{-q}{1-q} = \dfrac{q}{q-1}$

Plug that into the second equation and solve for $q$.
• November 13th 2013, 05:46 AM
vegasgunner
Re: help
thank you I solved it