Solve the system:

x^2 + y^2 = 100

-x + y = 2

I don't know where to start because my teacher never taught us how to solve a system of equations where the variables are squared. If someone could show me how to do this then that'd be great. THANKS!

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- Nov 12th 2013, 09:13 PMStephenSkinnerSystem of Equations HELP
Solve the system:

x^2 + y^2 = 100

-x + y = 2

I don't know where to start because my teacher never taught us how to solve a system of equations where the variables are squared. If someone could show me how to do this then that'd be great. THANKS! - Nov 12th 2013, 09:34 PMProve ItRe: System of Equations HELP
Write y in terms of x (from the second equation), substitute it into the first equation, then solve the quadratic.

- Nov 12th 2013, 09:50 PMStephenSkinnerRe: System of Equations HELP
Okay. I got:

x^2 + y^2 = 100

-x + y = 2 ------> y = x + 2

x^2 + (x + 2)^2 = 100

x^2 + x^2 + 4x + 4 = 100

2x^2 + 4x = 96

2x^2 + 4x - 96 = 0

(2x + 12)(x - 8)

2x + 12 = 0

2x = -12

x = -6

x - 8 = 0

x = 8

So from here would I plug both x-values in to my 'y = x + 2' equation? Thus giving me 2 solutions to the system of equations? Idk if I'm doing this right. - Nov 12th 2013, 09:53 PMStephenSkinnerRe: System of Equations HELP
Okay. I got:

x^2 + y^2 = 100

-x + y = 2 ------> y = x + 2

x^2 + (x + 2)^2 = 100

x^2 + x^2 + 4x + 4 = 100

2x^2 + 4x = 96

2x^2 + 4x - 96 = 0

(2x + 12)(x - 8)

2x + 12 = 0

2x = -12

x = -6

x - 8 = 0

x = 8

So from here would I plug both x-values in to my 'y = x + 2' equation? Thus giving me 2 solutions to the system of equations? Idk if I'm doing this right. - Nov 12th 2013, 10:08 PMSlipEternalRe: System of Equations HELP
, so you have the signs backwards. It should be (note: I factored out the 2). Hence . Now, plug those values in for .

Finally, plug in both sets of values you found for and to the first equation to make sure it is correct. - Nov 12th 2013, 10:41 PMStephenSkinnerRe: System of Equations HELP