Solve:
4 + log(base 3)(2 - x) = 9
I got:
log(base 3)(2 - x) = 5
2 - x = 3^5
2 - x = 243
-x = 241
x = -241
Don't think this is right can someone help me out? Thanks.
Your question was to solve $\displaystyle 4+\log_3(2-x) = 5$ and you solved $\displaystyle \log_3(2-x) = 5$. Those are not the same equations. To solve the first equation, subtract 4 from each side:
$\displaystyle \begin{align*}& \log_3(2-x) = 1 \\ \Rightarrow & 2-x = 3^1 = 3 \\ \Rightarrow & x = -1\end{align*}$.