Here are some questions that I can't solve...
factorization:
1.a^2x+2+2a^2+x
2.-(3+a)(5-b)+3c(b-5)
3.-a-b+3ab+3a^2
4.x^2-y^2+x-y
5.x^2-y^2+3x+3y
6.2c^2-8d^2+c-2d
That's all, hope you can help me
Thanks
Hello,Originally Posted by dgolverk
with your problems, you always have to seek equal factors at two summands:
to 1: $\displaystyle a^2x+2+2a^2+x=x(a^2+1)+2(a^2+1)=(a^2+1)(x+2)$
to 2: $\displaystyle -(3+a)(5-b)+3c(b-5)=(b-5)(3+a+3c)$
to 3: $\displaystyle -a-b+3ab+3a^2=-(a+b)+3a(a+b)=(a+b)(3a-1)$
to 4: $\displaystyle x^2-y^2+x-y=(x+y)(x-y)+(x-y)=$
$\displaystyle (x-y)(x+y+1)$
to 5: $\displaystyle x^2-y^2+3x+3y=(x+y)(x-y)+3(x+y)=$
$\displaystyle (x+y)(x-y+3)$
to 6: $\displaystyle 2c^2-8d^2+c-2d=2(c+2d)(c-2d)+(c+2d)=$
$\displaystyle (c-2d(2c+4d+1)$
Hope this was of some help.
Greetings
EB
Hello,Originally Posted by dgolverk
it's me again:
to 1.: $\displaystyle (b-a)=(-1)(a-b)$
$\displaystyle 3x(a-b)+4y(b-a) =(a-b)(3x-4y)$
to 2.: $\displaystyle 24x^2(d-c)+3x^2(-d+c)=(d-c)(24x^2-3x^2)=$
$\displaystyle 21x^2 \cdot (d-c)$
to 3.: $\displaystyle 3(a+b-c)-d(a+b-c)= (a+b-c)(3-d)$
Nice Weekend to you.
Greetings
EB