Factorization

• Mar 17th 2006, 07:11 AM
dgolverk
Factorization
Here are some questions that I can't solve...
factorization:
1.a^2x+2+2a^2+x
2.-(3+a)(5-b)+3c(b-5)
3.-a-b+3ab+3a^2
4.x^2-y^2+x-y
5.x^2-y^2+3x+3y
6.2c^2-8d^2+c-2d

That's all, hope you can help me :)
Thanks
• Mar 17th 2006, 08:24 AM
earboth
Quote:

Originally Posted by dgolverk
Here are some questions that I can't solve...
factorization:
1.a^2x+2+2a^2+x
2.-(3+a)(5-b)+3c(b-5)
3.-a-b+3ab+3a^2
4.x^2-y^2+x-y
5.x^2-y^2+3x+3y
6.2c^2-8d^2+c-2d

That's all, hope you can help me :)
Thanks

Hello,

with your problems, you always have to seek equal factors at two summands:

to 1: $a^2x+2+2a^2+x=x(a^2+1)+2(a^2+1)=(a^2+1)(x+2)$
to 2: $-(3+a)(5-b)+3c(b-5)=(b-5)(3+a+3c)$
to 3: $-a-b+3ab+3a^2=-(a+b)+3a(a+b)=(a+b)(3a-1)$
to 4: $x^2-y^2+x-y=(x+y)(x-y)+(x-y)=$
$(x-y)(x+y+1)$
to 5: $x^2-y^2+3x+3y=(x+y)(x-y)+3(x+y)=$
$(x+y)(x-y+3)$
to 6: $2c^2-8d^2+c-2d=2(c+2d)(c-2d)+(c+2d)=$
$(c-2d(2c+4d+1)$

Hope this was of some help.

Greetings

EB
• Mar 17th 2006, 09:10 AM
dgolverk
Thanks,
That was exactly what I was looking for :)
• Mar 17th 2006, 09:32 AM
dgolverk
Hmm..
While doing my homework I found 3 more problems...
1.3x(a-b)+4y(b-a) I don't understand how can I make two (b-a) or (a-b)
2.24X^2(d-c)+3x^2(-d+c)
3.3(a+b-c)-d(a+b-c)

Those are the 3 last questions in my homework...
Thanks again for helping!
• Mar 17th 2006, 12:28 PM
earboth
Quote:

Originally Posted by dgolverk
While doing my homework I found 3 more problems...
1.3x(a-b)+4y(b-a) I don't understand how can I make two (b-a) or (a-b)
2.24X^2(d-c)+3x^2(-d+c)
3.3(a+b-c)-d(a+b-c)

Those are the 3 last questions in my homework...
Thanks again for helping!

Hello,

it's me again:

to 1.: $(b-a)=(-1)(a-b)$
$3x(a-b)+4y(b-a) =(a-b)(3x-4y)$
to 2.: $24x^2(d-c)+3x^2(-d+c)=(d-c)(24x^2-3x^2)=$
$21x^2 \cdot (d-c)$
to 3.: $3(a+b-c)-d(a+b-c)= (a+b-c)(3-d)$

Nice Weekend to you.

Greetings

EB
• Mar 17th 2006, 11:11 PM
dgolverk
Thanks
I made a mistake in the last question it supposed to be like that:
3(a+b+c)-d(a+b-c)

What is the answer for that one?

and those:
x^3-xy^2+y^2+xy

x^4-y^4+y-x
• Mar 18th 2006, 10:44 AM
dgolverk
guys it's really urgent, that's for tomorrow...
Thanks