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Math Help - help

  1. #1
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    help

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  2. #2
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    Re: help

    Let x be the middle odd positive number, then we have
    ( x-2) + x + ( x+2) = 1/7 [ x ( x-2)(x+2)]
    3x = 1/7 [ x ( x^2 - 4 )]
    21x =x ( x^2-4) That gives x [ x^2 - 25 ] = 0
    Now I am sure you can conclude
    that the numbers are 3,5,7
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