Let x be the middle odd positive number, then we have

( x-2) + x + ( x+2) = 1/7 [ x ( x-2)(x+2)]

3x = 1/7 [ x ( x^2 - 4 )]

21x =x ( x^2-4) That gives x [ x^2 - 25 ] = 0

Now I am sure you can conclude

that the numbers are 3,5,7

Results 1 to 2 of 2

- November 7th 2013, 08:02 PM #1

- Joined
- Oct 2013
- From
- nevada
- Posts
- 58

- November 7th 2013, 09:18 PM #2

- Joined
- Jul 2012
- From
- INDIA
- Posts
- 860
- Thanks
- 218