2. ## Re: help

Let x be the middle odd positive number, then we have
( x-2) + x + ( x+2) = 1/7 [ x ( x-2)(x+2)]
3x = 1/7 [ x ( x^2 - 4 )]
21x =x ( x^2-4) That gives x [ x^2 - 25 ] = 0
Now I am sure you can conclude
that the numbers are 3,5,7