Let x be the middle odd positive number, then we have

( x-2) + x + ( x+2) = 1/7 [ x ( x-2)(x+2)]

3x = 1/7 [ x ( x^2 - 4 )]

21x =x ( x^2-4) That gives x [ x^2 - 25 ] = 0

Now I am sure you can conclude

that the numbers are 3,5,7

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- November 7th 2013, 09:02 PM #1

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- November 7th 2013, 10:18 PM #2

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