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Let x be the middle odd positive number, then we have ( x-2) + x + ( x+2) = 1/7 [ x ( x-2)(x+2)] 3x = 1/7 [ x ( x^2 - 4 )] 21x =x ( x^2-4) That gives x [ x^2 - 25 ] = 0 Now I am sure you can conclude that the numbers are 3,5,7