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- Nov 5th 2013, 10:12 AMvegasgunnerhelllp
- Nov 5th 2013, 10:33 AMSlipEternalRe: helllp
The points described are points with either $\displaystyle y = 2x$ or $\displaystyle x = 2y$. Let's solve for $\displaystyle y$ in the second equation: $\displaystyle y = \dfrac{1}{2}x$. Graph these two equations and see what you wind up with.