# Math Help - Simplified Form Question::Check

1. ## Simplified Form Question::Check

I got

$4,7,x^8,y^18,y$ --All in radicals..that is a y to the 18th power

$2x^4y^9$ radical 7y

2. $\sqrt {448x^8 y^{19} } = \sqrt {2^6 \cdot 7x^8 y^{19} } = 2^3 x^4 y^9 \sqrt {7y}$
Do you see how it works?

3. Originally Posted by Plato
$\sqrt {448x^8 y^{19} } = \sqrt {2^6 \cdot 7x^8 y^{19} } = 2^3 x^4 y^9 \sqrt {7y}$
Do you see how it works?
How did you get for the first part:
$2^3$ I got everything except for the $2^3$ I did get the 2 but no 3rd root.

4. Here is how it works.
$\begin{array}{l}
\sqrt {2^6 } = 2^3 \\
\sqrt {2^6 } = \left( {2^6 } \right)^{\frac{1}{2}} = 2^3 \\
\end{array}
$

$\left( {\frac{1}{2}} \right)\left( 6 \right) = 3$

5. Ok. Seems I messed up because as I tried to find out how I got 4,7 I played around with the numbers again and got 4, 28. Is this the correct answer?