$\displaystyle (x-a)(x-b)+h^2=0$, find the value of "h" when the roots of the equation are real(a>b). If The roots are $\displaystyle \alpha,\beta$,Then find the quadratic equations which have the roots of $\displaystyle (2\alpha+\beta),(\alpha+2\beta)$ByIn this problem i find the value of "h" like this h<=$\displaystyle \frac{a-b}{2}$ But, How can i find that quadratic equations by substituting...the correct substitution....