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Math Help - Quadratic equations

  1. #1
    Member srirahulan's Avatar
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    Post Quadratic equations

    (x-a)(x-b)+h^2=0, find the value of "h" when the roots of the equation are real(a>b). If The roots are \alpha,\beta,Then find the quadratic equations which have the roots of (2\alpha+\beta),(\alpha+2\beta) By the correct substitution....

    In this problem i find the value of "h" like this h<= \frac{a-b}{2} But, How can i find that quadratic equations by substituting...
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  2. #2
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    Re: Quadratic equations

    Expand and bring the given quadratic equation in the standard form then apply the discriminant rule to get h^2<((a-b)^2)/4

    For the second question form the equation k[x-(2a+b)][x-(a+2b)]=0 where k is any real number.
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  3. #3
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    Re: Quadratic equations

    Quadratic equations-23-oct-13-4.png
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