Results 1 to 2 of 2
Like Tree1Thanks
  • 1 Post By ibdutt

Math Help - factoring

  1. #1
    Super Member
    Joined
    Sep 2013
    From
    Portland
    Posts
    539
    Thanks
    73

    factoring

    if anyone has a quicker way I could factor this it would be appreciated.

    \frac{1}{2}(36-2x)\sqrt{x^2 - \frac{1}{4}(36 - 2x)^2}

    \frac{1}{2}-2(x-18)\sqrt{x^2 - \frac{1}{4}(36 - 2x)^2}

    \frac{1}{2}-2(x-18)\sqrt{x^2 - \frac{1}{4}(4x^2 -72x + 1296)

    \frac{1}{2}-2(x-18)\sqrt{x^2 - (x^2 - 36x + 324)}

    \frac{1}{2}-2(x-18)\sqrt{36x+324}

    \frac{1}{2}-2(x-18)\sqrt{36(x-9)

    \frac{1}{2}-2(x-18)6\sqrt{x-9}

    -6(x-18)\sqrt{x-9}

    thank you!!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Jul 2012
    From
    INDIA
    Posts
    834
    Thanks
    209

    Re: factoring

    factoring-23-oct-13.png
    Thanks from topsquark
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Factoring
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: May 19th 2010, 11:31 PM
  2. The art of factoring....
    Posted in the Algebra Forum
    Replies: 1
    Last Post: May 17th 2010, 07:48 AM
  3. Replies: 2
    Last Post: August 22nd 2009, 11:57 AM
  4. factoring
    Posted in the Math Topics Forum
    Replies: 2
    Last Post: July 21st 2008, 06:16 AM
  5. Replies: 3
    Last Post: November 6th 2006, 12:02 AM

Search Tags


/mathhelpforum @mathhelpforum