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  • 1 Post By ibdutt

Math Help - factoring

  1. #1
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    factoring

    if anyone has a quicker way I could factor this it would be appreciated.

    \frac{1}{2}(36-2x)\sqrt{x^2 - \frac{1}{4}(36 - 2x)^2}

    \frac{1}{2}-2(x-18)\sqrt{x^2 - \frac{1}{4}(36 - 2x)^2}

    \frac{1}{2}-2(x-18)\sqrt{x^2 - \frac{1}{4}(4x^2 -72x + 1296)

    \frac{1}{2}-2(x-18)\sqrt{x^2 - (x^2 - 36x + 324)}

    \frac{1}{2}-2(x-18)\sqrt{36x+324}

    \frac{1}{2}-2(x-18)\sqrt{36(x-9)

    \frac{1}{2}-2(x-18)6\sqrt{x-9}

    -6(x-18)\sqrt{x-9}

    thank you!!
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  2. #2
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    Re: factoring

    factoring-23-oct-13.png
    Thanks from topsquark
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