Hi,

Could some one show me how to do this,its all new to me so as simple as possible please,reasoning behind it etc.

Thanks guys.

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- Oct 22nd 2013, 06:38 AMLeatherneckTransposition of Formula
Hi,

Could some one show me how to do this,its all new to me so as simple as possible please,reasoning behind it etc.

Thanks guys. - Oct 22nd 2013, 07:04 AMSlipEternalRe: Transposition of Formula
I am assuming the ones that are not circled are not due, so I can help with one of those. Let's look at problem 35.

Let's read what is happening. On the left-hand side (LHS) of the equation, you have . On the right-hand side (RHS), you have times an expression containing . We want to isolate the expression containing . We want that coefficient to be 1. So, we divide both sides by 4a:

We still want to get alone. Currently, on the LHS of the equation, we don't have any terms with , but on the RHS, we have plus some term that does not contain any . So, we subtract from both sides of the equation:

Now we are done. We have on one side of the equation and everything that does not have an on the other. - Oct 22nd 2013, 08:03 AMHallsofIvyRe: Transposition of Formula
To solve for P, we note that P is only in the second fraction so we can simplify by subtracting the other fraction from both sides: . At this point there are a couple of different ways to continue.

1) Probably simplest for this problem. Multiply both sides by : . That gets P out of the denominator. We still have multiplied by . To undo that, we must divide both sides by . That gives [tex]\dfrac{q^2x^2}{q^2- y^2}= P^2[/itex]. The last step, of course, would be to take the square root of both sides.

1) Quicker but harder to see. Start by writing the as so your equation is . Now, "cross multiply"- that is, multiply both sides by to get rid of the two denominators: . Get alone on the right by dividing both sides by [tex]q^2- y^2[tex]. That leaves and now you can take the square root of both sides.

The general idea is this: You want to "solve" and equation for a given variable because it is NOT "by itself" on one side of the equation. Things have been done to it- it has been multiplied by something or something has been added or subtracted or it has been squared or cubed, etc. To get it by itself, you have to**undo**those things- do the opposite. And, of course, always do the same thing to both sides of the equation. - Oct 23rd 2013, 12:20 AMLeatherneckRe: Transposition of Formula
Not sure,I need practice.Thanks anyway

- Oct 23rd 2013, 12:21 AMLeatherneckRe: Transposition of Formula
Thanks