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Math Help - Solve equation

  1. #1
    Senior Member Paze's Avatar
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    Solve equation

    I'm having severe difficulties solving this equation:

    \frac{\sqrt{x^2-50x+1525}}{x-25}+\frac{\sqrt{x^2+400}}{x}=0

    I tried most conventional algebra methods but none seem to work! Thanks.
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  2. #2
    Senior Member Paze's Avatar
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    Re: Solve equation

    Really need help on this one. It's a string in a series of long calculus computations that are due for monday
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  3. #3
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    Re: Solve equation

    You can use conventional algebra methods

    \frac{\sqrt{x^2-50x+1525}}{x-25}=-\frac{\sqrt{x^2+400}}{x}

    Cross-multiply

    (x)\sqrt{x^2-50x+1525}=-(x-25)\sqrt{x^2+400}

    Then square both sides. It starts as a nasty equation but simplifies to something quite nice.
    Thanks from Paze
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  4. #4
    Senior Member Paze's Avatar
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    Re: Solve equation

    Quote Originally Posted by Shakarri View Post
    You can use conventional algebra methods

    \frac{\sqrt{x^2-50x+1525}}{x-25}=-\frac{\sqrt{x^2+400}}{x}

    Cross-multiply

    (x)\sqrt{x^2-50x+1525}=-(x-25)\sqrt{x^2+400}

    Then square both sides. It starts as a nasty equation but simplifies to something quite nice.
    Thanks. I realized later that \left((a+b)(\sqrt{c+d})\right)^2 actually simplifies to \left((a+b)^2(c+d)\right)

    I hadn't realized this before and it made the calculation that much easier! Thanks!
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