Results 1 to 4 of 4

Math Help - Simplifying

  1. #1
    Senior Member Paze's Avatar
    Joined
    Nov 2012
    From
    Iceland
    Posts
    379
    Thanks
    19

    Simplifying

    Wait, rephrasing this question
    Last edited by Paze; October 11th 2013 at 06:56 AM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    9,854
    Thanks
    321
    Awards
    1

    Re: Simplifying

    Quote Originally Posted by Paze View Post
    I have ran across a calculus problem where a maxima/minima was defined but in reality it wasn't.

    The reason was that I needed to simplify my equation.

    My question is two-fold:

    How do I simplify x^2-2x+26?

    Why is it so important to simplify equations? How does it change the outcome without changing the content? Thanks!

    The original differentiated equation was:

    \frac{x^2-2x+26}{(x-1)^2}=0
    Unless you want to factor the numerator over the reals, this is as simplified as it's going to get.
    \frac{x^2-2x+26}{(x-1)^2} = \frac{(x - (1 + 5i))(x - (1 - 5i))}{(x - 1)^2}

    I don't see how this helps, so I'd leave it in the form you put it in.

    In general you want to simplify the expression as much as you can. This is either for the sake of clarity or perhaps because you are going to use the expression later and you want to make it as "simple" as possible.

    -Dan
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member Paze's Avatar
    Joined
    Nov 2012
    From
    Iceland
    Posts
    379
    Thanks
    19

    Re: Simplifying

    Quote Originally Posted by topsquark View Post
    Unless you want to factor the numerator over the reals, this is as simplified as it's going to get.
    \frac{x^2-2x+26}{(x-1)^2} = \frac{(x - (1 + 5i))(x - (1 - 5i))}{(x - 1)^2}

    I don't see how this helps, so I'd leave it in the form you put it in.

    In general you want to simplify the expression as much as you can. This is either for the sake of clarity or perhaps because you are going to use the expression later and you want to make it as "simple" as possible.

    -Dan
    Thanks, Dan. I made a mistake in this thread which I had been dealing with for an hour but of course noticed as soon as I made a thread!

    However, my original question is still valid and has been clarified at: Simplifying to get the correct answer
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Senior Member
    Joined
    Sep 2013
    From
    USA
    Posts
    255
    Thanks
    114

    Re: Simplifying

    Quote Originally Posted by topsquark View Post
    Unless you want to factor the numerator over the reals, this is as simplified as it's going to get.
    \frac{x^2-2x+26}{(x-1)^2} = \frac{(x - (1 + 5i))(x - (1 - 5i))}{(x - 1)^2}

    I don't see how this helps, so I'd leave it in the form you put it in.

    In general you want to simplify the expression as much as you can. This is either for the sake of clarity or perhaps because you are going to use the expression later and you want to make it as "simple" as possible.

    -Dan
    I would define z = 1 + 5i, then the fraction becomes (x - z)(x - z*)/(x - 1)^2. Perhaps this would make the OP happier
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Need help simplifying
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: June 28th 2011, 07:10 PM
  2. simplifying an ode
    Posted in the Differential Equations Forum
    Replies: 0
    Last Post: May 17th 2011, 03:04 AM
  3. Some simplifying help.
    Posted in the Algebra Forum
    Replies: 1
    Last Post: September 24th 2009, 05:06 AM
  4. Help Simplifying
    Posted in the Algebra Forum
    Replies: 1
    Last Post: September 12th 2009, 08:01 AM
  5. simplifying
    Posted in the Algebra Forum
    Replies: 1
    Last Post: December 2nd 2008, 11:53 AM

Search Tags


/mathhelpforum @mathhelpforum