Maple says that why is each of the|Xi-Xj| multiplied by two? Is it that |Xi - Xj| =|Xj - Xi|? I had not realized that double summation multiplies sums every combination of Xi and Xj
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Originally Posted by kingsolomonsgrave Is it that |Xi - Xj| =|Xj - Xi|? Yes. There are nine ordered pairs , and three of them (with equal elements) give rise to . The other six are split into three pairs because . If you want just , you can denote it by .
On line 4, you keep i=1 for all three terms. On line 5, you keep i=2 for all three terms. Then on line 6, you keep i=3 for all three terms. It should read (beginning on line 4):
Originally Posted by ibdutt Sorry i made some typing mistake, it shd be as under
Yes, that is correct.
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