1. ## Solving this Quadratic Equation!

$\displaystyle x^2$$\displaystyle ²$$\displaystyle + 2x - 5 = 0$

I'm in my GCSE year at school.

the first x is squared, the 2 wont show up for some reason

2. Completing the square:

$\displaystyle x^2+2x-5=0$

$\displaystyle x^2+2x = 5$

$\displaystyle x^2+2x+1=5+1$

$\displaystyle (x+1)^2=6$

$\displaystyle x+1=\pm \sqrt{6}$

$\displaystyle x=-1\pm \sqrt{6}$

$\displaystyle x = \frac{-(2) \pm \sqrt{(2)^2 - 4(1)(-5)}}{2(1)}$

$\displaystyle x=\frac{-2 \pm \sqrt{24}}{2}$

$\displaystyle x=\frac{-2\pm 2\sqrt{6}}{2}$

$\displaystyle x=-1 \pm \sqrt{6}$

3. Wow that answer was great! I'm not very good at maths though and that Quadratic formula as just babble to me haha, sorry about that.

Could you explain where the one came from?
I learn easier with an explanation, formula is a new language for me haha!

Thank you!