$\displaystyle x^2$$\displaystyle ²$$\displaystyle + 2x - 5 = 0
$
Can you answer this please?? Showing all working out! Thanks!
I'm in my GCSE year at school.
the first x is squared, the 2 wont show up for some reason
$\displaystyle x^2$$\displaystyle ²$$\displaystyle + 2x - 5 = 0
$
Can you answer this please?? Showing all working out! Thanks!
I'm in my GCSE year at school.
the first x is squared, the 2 wont show up for some reason
Completing the square:
$\displaystyle x^2+2x-5=0$
$\displaystyle x^2+2x = 5$
$\displaystyle x^2+2x+1=5+1$
$\displaystyle (x+1)^2=6$
$\displaystyle x+1=\pm \sqrt{6}$
$\displaystyle x=-1\pm \sqrt{6}$
GFSQ (General Formula for Solution of Quadratics) i.e. Quadratic Formula:
$\displaystyle x = \frac{-(2) \pm \sqrt{(2)^2 - 4(1)(-5)}}{2(1)}$
$\displaystyle x=\frac{-2 \pm \sqrt{24}}{2}$
$\displaystyle x=\frac{-2\pm 2\sqrt{6}}{2}$
$\displaystyle x=-1 \pm \sqrt{6}$
Wow that answer was great! I'm not very good at maths though and that Quadratic formula as just babble to me haha, sorry about that.
Could you explain where the one came from?
I learn easier with an explanation, formula is a new language for me haha!
Thank you!