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  1. #1
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    functions

    f(x) = 2x+1
    g(x) = 3x-5

    find g^-1 of f^-1 of 2
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by DINOCALC09 View Post
    f(x) = 2x+1
    g(x) = 3x-5

    find g^-1 of f^-1 of 2
    Let g(x) = y_1 = 3x - 5

    for g^{-1} switch x and y and solve for y

    so, x = 3y_1 - 5

    y_1 = \frac {x + 5}3

    thus, g^{-1}(x) = \frac {x + 5}3

    similarly, f^{-1}(x) = \frac {x - 1}2


    now can you find g^{-1} \circ f^{-1}(x) = g^{-1} \left( f^{-1} (x) \right)?
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