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Math Help - complex numbers

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    complex numbers

    solve the equation z^3+64=0, giving your answer in exponential form
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  2. #2
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    Re: complex numbers

    Quote Originally Posted by cxz7410123 View Post
    solve the equation z^3+64=0, giving your answer in exponential form
    Let \rho = 4\exp \left( {\frac{{\pi i}}{3}} \right) and \eta  = \exp \left( {\frac{{2\pi i}}{3}} \right).

    Your roots are \rho\cdot \eta^k where k=0,~1,~2.
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