# Thread: complex numbers

1. ## complex numbers

solve the equation z^3+64=0, giving your answer in exponential form

2. ## Re: complex numbers

Originally Posted by cxz7410123
solve the equation z^3+64=0, giving your answer in exponential form
Let $\rho = 4\exp \left( {\frac{{\pi i}}{3}} \right)$ and $\eta = \exp \left( {\frac{{2\pi i}}{3}} \right)$.

Your roots are $\rho\cdot \eta^k$ where $k=0,~1,~2$.