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Math Help - Determining Manipulated Co-ordinates.

  1. #1
    Super Member sakonpure6's Avatar
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    Determining Manipulated Co-ordinates.

    Hey, I ran across this question in my text book.
    Dikembe has reflected the gunction g(x) = x^3 in the x-axis, vertically compressed it by a factor of 2/3, horizontally translated it 13 units to the right, and vertically translated it 13 units down. Three points on the resulting curve are (11, -23/3) , (13,-13), abd (15,-55/3). Determine the original co-ordinates of these three points on g(x).
    So I concluded the following transformed cubic function f(x) = 2/3 (x-13)^3 -13 , and the equation to convert both x and y co-ordinates back to their original (x-13, 3/2y+13). Now in the textbook, the answers are (-2,8) , (0,0) and (2,-8). My equation works for getting the correct x - int , but not the y. Where did I go wrong?

    Would it be a better idea to use the original function g(x) to find the corresponding y-value to the found x values? But If I do we would get (-2,-8) , (0,0) and (2,8).


    Thank you in advance.
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  2. #2
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    Re: Determining Manipulated Co-ordinates.

    Taking the symmetry with respect to the x-axis, change the sign of the furnction, you don't have a translation yet. That part you did not do correctly. fix this one then we'll see what's next
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