# Thread: Competition Question with Imaginary Roots

1. ## Competition Question with Imaginary Roots

Came across this problem on a math competition.

The equation $\displaystyle 3x^2 + 4x + k = 0$ has two imaginary roots. Which of the following is a true statement about the value of $\displaystyle k$?

a) $\displaystyle k < 0$
b) $\displaystyle k < -2$
c) $\displaystyle k > 2$
d) $\displaystyle k > 0$

I'm having a hard time setting up a condition for k.

2. ## Re: Competition Question with Imaginary Roots

Originally Posted by ReneG
Came across this problem on a math competition.
The equation $\displaystyle 3x^2 + 4x + k = 0$ has two imaginary roots. Which of the following is a true statement about the value of $\displaystyle k$?
a) $\displaystyle k < 0$
b) $\displaystyle k < -2$
c) $\displaystyle k > 2$
d) $\displaystyle k > 0$
I'm having a hard time setting up a condition for k.
I am puzzled by this question because the correct answer is $\displaystyle k>\frac{4}{3}~.$

Use the discriminate, $\displaystyle b^2-4ac<0$ or $\displaystyle 16-12k<0$.

The closest answer is c). But that is not the exact answer.

3. ## Re: Competition Question with Imaginary Roots

I'm going to guess and say that the problem stated somewhere that k was an integer

4. ## Re: Competition Question with Imaginary Roots

Surely the problem is not exactly as given here. The equation $\displaystyle 3x^2+ 4x+ 4k= 0$ can have complex roots but cannot have imaginary roots.

5. ## Re: Competition Question with Imaginary Roots

Originally Posted by HallsofIvy
Surely the problem is not exactly as given here. The equation $\displaystyle 3x^2+ 4x+ 4k= 0$ can have complex roots but cannot have imaginary roots.
Whereas you are absolutely correct, I was part of the mathematics contest community long enough to know many in the mathematics education community use imaginary number and complex number interchangeably. I assure you it is futile to even try to correct them. Thus having seen that this is an old contest question, I assumed the worst.