We have the function f(x)= x(x-3)^2 , so in standard form we would get .........+ 9 . Right, and that means it is the y-int. So why doesn't this function hit the y-int at 9 ? is it because we multiply x through out?
Follow Math Help Forum on Facebook and Google+
Originally Posted by sakonpure6 is it because we multiply x through out? Yes.
View Tag Cloud