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Math Help - Graphing Question

  1. #1
    Senior Member sakonpure6's Avatar
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    Graphing Question

    We have the function f(x)= x(x-3)^2 , so in standard form we would get .........+ 9 . Right, and that means it is the y-int. So why doesn't this function hit the y-int at 9 ?

    is it because we multiply x through out?
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  2. #2
    MHF Contributor
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    Re: Graphing Question

    Quote Originally Posted by sakonpure6 View Post
    is it because we multiply x through out?
    Yes. x(x-3)^2=x^3-6x^2+9x
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