# Graphing Question

• Sep 26th 2013, 02:03 PM
sakonpure6
Graphing Question
We have the function f(x)= x(x-3)^2 , so in standard form we would get .........+ 9 . Right, and that means it is the y-int. So why doesn't this function hit the y-int at 9 ?

is it because we multiply x through out?
• Sep 26th 2013, 02:09 PM
emakarov
Re: Graphing Question
Quote:

Originally Posted by sakonpure6
is it because we multiply x through out?

Yes. $x(x-3)^2=x^3-6x^2+9x$