We have the function f(x)= x(x-3)^2 , so in standard form we would get .........+ 9 . Right, and that means it is the y-int. So why doesn't this function hit the y-int at 9 ?

is it because we multiply x through out?

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- September 26th 2013, 03:03 PMsakonpure6Graphing Question
We have the function f(x)= x(x-3)^2 , so in standard form we would get .........+ 9 . Right, and that means it is the y-int. So why doesn't this function hit the y-int at 9 ?

is it because we multiply x through out? - September 26th 2013, 03:09 PMemakarovRe: Graphing Question