From here you should notice that you could extract coefficients(common factors) out of the brackets, along with their respective exponents.
I notice a bit of how you are getting that but not entirely. I downloaded an older text book that deals with nothing but factoring. Maybe it'll help but maybe you could explain a little bit. Sorry, I have been stuck teaching everything to myself and sometimes it is a bit difficult. Thank you!
hey! I think I got it! thanks so much
let me go over my steps:
I start with (6-3x)^4 + x[4(6-3x)^3(-3)]
take out the binomial (6-3x)^3 giving me (6-3x)^3[(6-3x) + x(4(-3))
next I have (6-3x)^3[6-3x-12x]
then, (6-3x)^3[6-15x]
factor out 3 of the right binomial for 3(6-3x)^3(2-5x)
then factor out the coefficient of the the left binomial with the exponent to 3^1(3^3)(2-x)(2-5x)
and a final answer of
3^4(2-x)(2-5x)