I am working on being better at factor but I could use some help.
this (6-3x)^4 + x[4(6-3x)^3(-3)] factors to (6-3x)^3[(6-3x)-12x] to 3(6-3x)^3(2-5x)
looking for some help on how this is done. thank you.
I notice a bit of how you are getting that but not entirely. I downloaded an older text book that deals with nothing but factoring. Maybe it'll help but maybe you could explain a little bit. Sorry, I have been stuck teaching everything to myself and sometimes it is a bit difficult. Thank you!
See that $\displaystyle (6-3x) = 3(2-x) \text{ and } (6-15x) = 3 (2-5x) $.
So from where I left off in my last post,
$\displaystyle (6-3x)^3(6-15x)= (3(2-x))^3(3)(2-5x) =3^33^1(2-x)^3(2-5x) = 3^4(2-x)^3(2-5x)=\cdots $
Let me know if you still need some clarification.
hey! I think I got it! thanks so much
let me go over my steps:
I start with (6-3x)^4 + x[4(6-3x)^3(-3)]
take out the binomial (6-3x)^3 giving me (6-3x)^3[(6-3x) + x(4(-3))
next I have (6-3x)^3[6-3x-12x]
then, (6-3x)^3[6-15x]
factor out 3 of the right binomial for 3(6-3x)^3(2-5x)
then factor out the coefficient of the the left binomial with the exponent to 3^1(3^3)(2-x)(2-5x)
and a final answer of
3^4(2-x)(2-5x)