No that is exactly what you have to do.
Would appreciate some guidance on the problem below:
Solve Log[base 25](6x + 25) + Log[base 5](x + 25) = 5, x a Natural number
To solve I tried converting to a single base using Log[base A]x = Log[base B]x / Log[base B]A which gives:
Log[base 25](6x + 25) = Log[base 5](6x + 25) / Log[base 5]25 = Log[base 5](6x+25) / 2
So the equation becomes:
Log[base 5](6x + 25) / 2 + Log[base 5](x + 25) = 5
Log[base 5](6x + 25) + 2Log[base 5](x + 25) = 10
Log[base 5](6x + 25) + Log[base 5](x + 25)^2 = 10
Log[base 5](6x + 25)(x + 25)^2 = 10
5^10 = (6x +25)(x +25)^2
This seems like a nasty polynomial to solve - is there a simpler approach to the problem?
Thanks in advance
Corbomite1
Here is some advice on notation.
You can learn to post symbols. It really is so easy. And it makes most of us more willing to find out how to help.
This subforum will help you with the code. Once you begin, you quickly learn the code.
[TEX]\log_{25}(6x+25)+\log_{5}(x+25)=5 [/TEX] gives
If you click on the “go advanced tab” you should see on the tool-bar. That gives the [TEX]..[/TEX] wrap. Your LaTeX code goes between them.