Results 1 to 6 of 6
Like Tree3Thanks
  • 1 Post By votan
  • 1 Post By votan
  • 1 Post By johng

Math Help - Algebra 1 Parameter Changes...Changing Points

  1. #1
    Senior Member nycmath's Avatar
    Joined
    Jan 2013
    From
    Bronx, NY
    Posts
    396
    Thanks
    4

    Algebra 1 Parameter Changes...Changing Points

    I posted a new thread yesterday which no one has replied to. I simply want to know how to find new points using the information.

    Sample:

    Change m(x) to m(x+4) given the following two points:
    (-5,5)-->

    (0,0)-->

    The arrow indicates that the given points must be changed. In other words, I must find new coordinates using m(x+4).

    How is this done?

    Please, help me. See picture.
    Attached Thumbnails Attached Thumbnails Algebra 1 Parameter Changes...Changing Points-733791_10201176161143530_1792262717_n.jpg  
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member
    Joined
    Sep 2013
    From
    USA
    Posts
    255
    Thanks
    114

    Re: Algebra 1 Parameter Changes...Changing Points

    the first problem:
    eqauation of graph as given x(x+6)
    replace x by (x+4)
    new equation: (x+4)(x+10)
    for x = -5 y = -5

    do the other problems the same way. The exponential graph is 2^x.
    Thanks from nycmath
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member nycmath's Avatar
    Joined
    Jan 2013
    From
    Bronx, NY
    Posts
    396
    Thanks
    4

    Re: Algebra 1 Parameter Changes...Changing Points

    Thanks for your reply but I am still a bit lost. Your said equation but there is no equal sign. If (-5,5) and (0,0) is given, what would be the new points? Can you please do this one for me in full? I can then use your steps as a guide to answer the rest? What about the graph for q(x)? How is that done? Please, see attachment to view q(x). Thank you very much in advanced.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Senior Member
    Joined
    Sep 2013
    From
    USA
    Posts
    255
    Thanks
    114

    Re: Algebra 1 Parameter Changes...Changing Points

    first put negative sign in front of x in the original equation. the answer should be corrected accordingly.

    the equation you construct from the graph.
    the first graph is a parabola concave downward. then you could write it as -(x-a)(x-b). the negative sign in front of the bracket is because the parabola is concave downward. a and b are the x-intercepts. a=0 from the graph, b=-6 from the graph. that yields the equation of the parabola -x(x+6). now replace x in this equation by x+4 to obtain the new equation. fix x=-5 in the new equation and find y using the new equation.
    Last edited by votan; September 20th 2013 at 10:23 AM.
    Thanks from nycmath
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Senior Member nycmath's Avatar
    Joined
    Jan 2013
    From
    Bronx, NY
    Posts
    396
    Thanks
    4

    Re: Algebra 1 Parameter Changes...Changing Points

    I just realized that my name is exposed on this sheet of paper. How can I delete this uploaded picture? I do not want my name on the internet
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Super Member
    Joined
    Dec 2012
    From
    Athens, OH, USA
    Posts
    617
    Thanks
    250

    Re: Algebra 1 Parameter Changes...Changing Points

    Hi,
    First look at the attachment.

    Algebra 1 Parameter Changes...Changing Points-mhfalgebra2a.png

    So for a function such as y=g(x-3)-2, this is a translate of the function y=g(x). What is the translation (a,b)? It's (3,-2); i.e. points on the graph of g are shifted to the right by 3 and down by -2. So if (5,4) is a point on the graph of g,
    (8,2) is a point of the translated graph y=g(x-3)-2.

    Notice the lack of symmetry in the treatment of x and y coordinates. If the translated equation is y=g(x+a)+b, the corresponding translation is (-a,b). I assume your teacher (or text book) gives some sort of justification for all this.

    From the title of your homework, it looks as though you are working toward also scaling the graph of a function. Given y=f(x), the scaled graph has equation y=af(bx). Here the the graph is stretched (shrunk) in the y-direction by the factor a and is stretched (shrunk) in the x-direction by the factor 1/b.

    I hope this helps.
    Thanks from nycmath
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Algebra 1 Parameter Changes
    Posted in the Algebra Forum
    Replies: 1
    Last Post: September 20th 2013, 05:11 PM
  2. Replies: 4
    Last Post: March 30th 2013, 05:33 PM
  3. Algebra, points of intersection
    Posted in the Algebra Forum
    Replies: 3
    Last Post: February 17th 2013, 05:04 AM
  4. hypothesis testing: parameter 0 against parameter positive.
    Posted in the Advanced Statistics Forum
    Replies: 0
    Last Post: February 10th 2011, 02:49 PM
  5. Use algebra to identify the points of the 2-cycle?
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: March 12th 2009, 04:13 PM

Search Tags


/mathhelpforum @mathhelpforum