Hello. Concerning this attachment, I am concerned about part c and d. I would someone to help me answer this question. Please, see attachment. Thanks again.
If you graph out the points you find that the data is exponential growth, so in other words, the model starts linear, but then it takes a big turn up, increasing rapidly. As long as the line is going up and down, it should be smooth.
If the curve is exponential, then the data can't be shown as a linear model, instead it is another type of model.
The data are a funtion of the form p(t). It starts linear then it levels up bending downard slowly with slope approching 0.
Yes, the data can be represented by a smooth curve.
No, the graph cannot be modeled by a straight line. It has an asymptotic trend as t increases.
I plotted every point and my picture is that of a linear function. Are you sure that the given points represent a continuous smooth curve? Thanks again for your time and reply. Can you plot the given points and show me a picture of what this model looks like on the xy- plane? I can really use your help.
The limited data we have is not sufficient to determine what type of function that would be. My wild guess it would be something of the form a(b + e^-x). It cannot be a branch of a prabola because y does not vary as x^2
I tried a few fit functions and the best I got was actually the parabola. (The red curve.) Since it was a question I have also included the linear fit (in blue). You can easily see that the linear fit just doesn't work right. The only thing I'll say about the exponential fit is that it was really really ugly and did a lousy job. (I thought it would work, too.) See image below.
-Dan