# Thread: basic fraction question

1. ## basic fraction question

If I have $\frac{(y^{3}-1)}{(y-1)}$, can I simply factor out $y^2$, cancel out the $\frac{(y-1)}{(y-1)}$, leaving me with $y^2$?

2. ## Re: basic fraction question

Originally Posted by john95
If I have $\frac{(y^{3}-1)}{(y-1)}$, can I simply factor out $y^2$, cancel out the $\frac{(y-1)}{(y-1)}$, leaving me with $y^2$?
Absolutely not. You have the difference of two cubes:
$(y^3-1)=(y-1)(y^2+y+1)~.$

Thanks