# basic fraction question

• Sep 18th 2013, 03:28 PM
john95
basic fraction question
If I have $\frac{(y^{3}-1)}{(y-1)}$, can I simply factor out $y^2$, cancel out the $\frac{(y-1)}{(y-1)}$, leaving me with $y^2$?
• Sep 18th 2013, 03:49 PM
Plato
Re: basic fraction question
Quote:

Originally Posted by john95
If I have $\frac{(y^{3}-1)}{(y-1)}$, can I simply factor out $y^2$, cancel out the $\frac{(y-1)}{(y-1)}$, leaving me with $y^2$?

Absolutely not. You have the difference of two cubes:
$(y^3-1)=(y-1)(y^2+y+1)~.$
• Sep 18th 2013, 04:02 PM
john95
Re: basic fraction question
Thanks