If I have $\displaystyle \frac{(y^{3}-1)}{(y-1)}$, can I simply factor out $\displaystyle y^2$, cancel out the $\displaystyle \frac{(y-1)}{(y-1)}$, leaving me with $\displaystyle y^2$?

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- Sep 18th 2013, 03:28 PMjohn95basic fraction question
If I have $\displaystyle \frac{(y^{3}-1)}{(y-1)}$, can I simply factor out $\displaystyle y^2$, cancel out the $\displaystyle \frac{(y-1)}{(y-1)}$, leaving me with $\displaystyle y^2$?

- Sep 18th 2013, 03:49 PMPlatoRe: basic fraction question
- Sep 18th 2013, 04:02 PMjohn95Re: basic fraction question
Thanks