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Math Help - Standard to Vertex Form

  1. #1
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    Exclamation Standard to Vertex Form

    Alright, so I am trying to convert this formula to vertex form.

    0.5x2-8x+33

    Here is what I have so far: (Am I doing this correctly)?

    0.5(x2-6x)+33
    0.5(x2-6x+9)+33

    This is where I get stuck because I don't think I am completing the square correctly.. :c
    Last edited by michellederz; September 17th 2013 at 05:45 PM.
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  2. #2
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    Re: Standard to Vertex Form

    Quote Originally Posted by michellederz View Post
    Alright, so I am trying to convert this formula to vertex form.

    0.5x2-8x+33

    Here is what I have so far: (Am I doing this correctly)?

    0.5(x2-6x)+33
    0.5(x2-6x+9)+33

    This is where I get stuck because I don't think I am completing the square correctly.. :c
    You have the correct method, but where did the 6 come from in line 3?

    \frac{1}{2}x^2 - 8x + 33 = \frac{1}{2}(x^2 - 16x) + 33

    = \frac{1}{2} (x^2 - 8x + 16 - 16) + 33

    Can you finish it?

    -Dan
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