Solve the following equation for X?
-2xe^{-6x}+x^{2}e^{-6x}=0
I posted a forum thread similar to this but this one includes e.. Not sure how to solve for x when e is involved..
In the previous thread I posted, you just took the exponents that created a quadratic and solved for x that way. So would this be how you solve it?
-6x+2-6x=0
-12x+2=0
From here you would use the quadratic equation and get the answers 24 , 0
Would this be correct..?