Solve the following equation for X?

-2xe^{-6x}+x^{2}e^{-6x}=0

I posted a forum thread similar to this but this one includes e.. Not sure how to solve for x when e is involved..

In the previous thread I posted, you just took the exponents that created a quadratic and solved for x that way. So would this be how you solve it?

-6x+2-6x=0

-12x+2=0

From here you would use the quadratic equation and get the answers 24 , 0

Would this be correct..?