3^2n+1 x (1/6)^n = 2^2-n x 8^n
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Do you mean (3^(2n+1))(1/6)^n= (2^(2-n))8^n?
It helps to know that 6= 2(3) and 8= 2^n. Write everything in powers of 2 and 3
(The fact that there is no power of 3 on the right is something of a "giveaway"!)
Last edited by HallsofIvy; Sep 15th 2013 at 12:13 PM.
Stuck at this step
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