lg (4^p - 4) - p lg 2 = lg 3 I got to lg (4^p-4) - lg 2^p(3) - lg 3 = 0 And an answer of 9.58, but when checking back, it seems wrong. Please help Thanks
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One of the laws of logs you need to use is $\displaystyle log(A)-log(B)=log(\frac{A}{B})$ Similarly $\displaystyle log(A)+log(B)=log(AB)$
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