Since I could not edit the post here is the original problem and solution:

we have the following function y= -2(f(2(x+5)) -4 and a point (2,3). We are asked to find the "image" of (2,3) on the given function.

So first of all (2,3) means that y=3 and x=2 which means that 3=f(2).

To solve for the "image" x, we must do the following 2(x+5)=2 since f(2) must be related to f(2(x+5). Solve for x.

2(x+5)=2

x=1-5

x=-4

Now to solve for the "image" of y. We know that 3=f(2)=f(2(x+5)) So..

y=-2(f(2(x+5))-4

y= -2(f(2))-4

y= -2(3) -4

y= -6-4

y=-10

There fore the image coordinate of (2,3) on y= -2 (f(2(x+5))-4 is (-4,10).