Nvm, got it. Sorry for the inconvenience.
Since I could not edit the post here is the original problem and solution:
we have the following function y= -2(f(2(x+5)) -4 and a point (2,3). We are asked to find the "image" of (2,3) on the given function.
So first of all (2,3) means that y=3 and x=2 which means that 3=f(2).
To solve for the "image" x, we must do the following 2(x+5)=2 since f(2) must be related to f(2(x+5). Solve for x.
2(x+5)=2
x=1-5
x=-4
Now to solve for the "image" of y. We know that 3=f(2)=f(2(x+5)) So..
y=-2(f(2(x+5))-4
y= -2(f(2))-4
y= -2(3) -4
y= -6-4
y=-10
There fore the image coordinate of (2,3) on y= -2 (f(2(x+5))-4 is (-4,10).