Find the values of x that makes (2x-1)/(x-5)(x+3) an indeterminate.
Really confused. Please help.
Thanks Beth
Do you mean undefined? Undefined happens when you divide non-zero by zero, thus, $\displaystyle (x-5)(x+3)=0$ Thus, $\displaystyle -3,5$. Now indeterminate is when you divide zero by zero. But the problem is non of -3 or 5 make the numerator $\displaystyle 2x-1$ zero. Because, $\displaystyle 2(5)-1\not = 0$ and $\displaystyle 2(-3)-1\not =0$ thus, this fraction is never indeterminate. It is however undefined for -3,5 if that you were asking.Originally Posted by Bethfor88
As I was trying to show you, there's a difference between indeterminate and undefined, which ThePerfectHacker has explained now.
I would like to add though that 0/0 isn't the only possible indeterminate form, there exist others mostly involving infinity and/or 0.