Thread: Indeterminate?

Find the values of x that makes (2x-1)/(x-5)(x+3) an indeterminate.

Really confused. Please help.
Thanks Beth

What do you mean by "an indeterminate" here?

Is it the function and are you looking where it isn't defined? Check for what values of x the denominator becomes 0.

Find the values of x that makes (2x-1)/(x-5)(x+3) an indeterminate.

Really confused. Please help.
Thanks Beth

Originally Posted by Bethfor88

Find the values of x that makes (2x-1)/(x-5)(x+3) an indeterminate.

Really confused. Please help.
Thanks Beth

Hello,

it's me again:

Please look at College/University; Algebra. TD! has given an answer already.
If this answer isn't sufficient, you have to explain in detail what kind of problem you like to solve.

Greetings

EB

Originally Posted by Bethfor88

Find the values of x that makes (2x-1)/(x-5)(x+3) an indeterminate.

Really confused. Please help.
Thanks Beth

Do you mean undefined? Undefined happens when you divide non-zero by zero, thus, Thus, . Now indeterminate is when you divide zero by zero. But the problem is non of -3 or 5 make the numerator zero. Because, and thus, this fraction is never indeterminate. It is however undefined for -3,5 if that you were asking.

Bethfor88 Do not make duplicate threads
Also post this question in the appropriate section, this has nothing to do with College/University Algebra.

As I was trying to show you, there's a difference between indeterminate and undefined, which ThePerfectHacker has explained now.

I would like to add though that 0/0 isn't the only possible indeterminate form, there exist others mostly involving infinity and/or 0.