# Indeterminate?

• March 15th 2006, 12:19 PM
Bethfor88
Indeterminate?
Find the values of x that makes (2x-1)/(x-5)(x+3) an indeterminate.

Thanks Beth
• March 15th 2006, 12:29 PM
TD!
What do you mean by "an indeterminate" here?

Is it the function $\frac{{2x - 1}}{{\left( {x - 5} \right)\left( {x + 3} \right)}}$ and are you looking where it isn't defined? Check for what values of x the denominator becomes 0.
• March 15th 2006, 12:29 PM
Bethfor88
1 more question
Find the values of x that makes (2x-1)/(x-5)(x+3) an indeterminate.

Thanks Beth
• March 15th 2006, 12:40 PM
earboth
Quote:

Originally Posted by Bethfor88
Find the values of x that makes (2x-1)/(x-5)(x+3) an indeterminate.

Thanks Beth

Hello,

it's me again:

Please look at College/University; Algebra. TD! has given an answer already.
If this answer isn't sufficient, you have to explain in detail what kind of problem you like to solve.

Greetings

EB
• March 15th 2006, 12:43 PM
ThePerfectHacker
Quote:

Originally Posted by Bethfor88
Find the values of x that makes (2x-1)/(x-5)(x+3) an indeterminate.

Do you mean undefined? Undefined happens when you divide non-zero by zero, thus, $(x-5)(x+3)=0$ Thus, $-3,5$. Now indeterminate is when you divide zero by zero. But the problem is non of -3 or 5 make the numerator $2x-1$ zero. Because, $2(5)-1\not = 0$ and $2(-3)-1\not =0$ thus, this fraction is never indeterminate. It is however undefined for -3,5 if that you were asking.