• Mar 15th 2006, 11:01 AM
Bethfor88
I need to solve for ALL values of x:
(5(x-4)/6) + ((x+4)/12) = (2x/3) + 1

Beth
• Mar 15th 2006, 11:11 AM
earboth
Quote:

Originally Posted by Bethfor88
I need to solve for ALL values of x:
(5(x-4)/6) + ((x+4)/12) = (2x/3) + 1

Beth

Hello,

multiply your equation by 12 (it's the common denominator of all the fractions) and you'll get:
$\frac{5(x-4)\cdot 12}{6}+\frac{(x+4)\cdot 12}{12}=\frac{2x\cdot 12}{3}+1\cdot12$
simplify to:
10(x-4)+(x+4)=8x+12
3x=48
x=16

There are no other solutions.

Greetings

EB
• Mar 15th 2006, 11:13 AM
Bethfor88
Thanks that helped :D