I have to simplify this to get the equation of a circle: (x-4)^2 +4^2 + (x-2)^2 - 2^2 +11 = 0 I get: (x-4)^2 + (x-2)^2 +16 + 4 + 11 = 0 (x-4)^2 + (x-2)^2 = -31 ....where am I going wrong?

Follow Math Help Forum on Facebook and Google+

Originally Posted by GAdams (x-4)^2 +4^2 + (x-2)^2 - 2^2 +11 = 0 At first, this is not a circle, it's just a parabola. May be you mean which is clearly, an imaginary circle.

Originally Posted by Krizalid At first, this is not a circle, it's just a parabola. May be you mean which is clearly, an imaginary circle. Here's what I started with: x^2 - 8x + y^2 + 4y + 11 = 0 I completed teh square for the first couple of expressions and got to where I was in my first post.

Originally Posted by GAdams Here's what I started with: x^2 - 8x + y^2 + 4y + 11 = 0 I completed teh square for the first couple of expressions and got to where I was in my first post. that's incorrect then which is a circle centered at (4,-2) with radius 3

View Tag Cloud