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Math Help - e and ln Problem

  1. #1
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    e and ln Problem

    3e^{3x} = 3x^{2}

    \dfrac{3e^{3x}}{3} = \dfrac{3x^{2}}{3}

    e^{3x} = x^{2}

    \ln(e^{3x}) = \ln(x^{2})

    3x = \ln(x^{2}) - What trick could I do here?
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  2. #2
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    Re: e and ln Problem

    remember laws of logarithms
    log(a^m) = m log a
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  3. #3
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    Re: e and ln Problem

    Quote Originally Posted by Jason76 View Post
    3e^{3x} = 3x^{2}

    \dfrac{3e^{3x}}{3} = \dfrac{3x^{2}}{3}

    e^{3x} = x^{2}
    Write that as f(x)=e^{3x}-x^2. Look at the graph.

    Use a numerical method such as Newton's approximation to find the root.
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