I do not understand how to do these problems. Is there anyone who understands these?
3x/y - x
______________
2y - y/x
the easiest way i'm seeing is to just combine the fractions in the numerator and the denominator and then simplify:
$\displaystyle \frac {\frac {3x}y - x}{2y - \frac yx} = \frac {\frac {3x - xy}y}{\frac {2xy - y}x} = \frac {x(3 - y)}y \cdot \frac x{y(2x - 1)} = \frac {x^2 (3 - y)}{y^2 (2x - 1)}$
...or yes, you can do it Krizalid's way. i thought about it, but for some reason i decided to do it the hard way.