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Math Help - Dividing mass lifted by parties

  1. #1
    Senior Member Paze's Avatar
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    Dividing mass lifted by parties

    Say 4 men lift 200 kilos. Can I simply divide 200 by 4 to get 50kg each...So they lifted 50kilos each (given the same posture and dimensions of the lift)?

    Or is the calculation more complex?
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  2. #2
    MHF Contributor

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    Re: Dividing mass lifted by parties

    Quote Originally Posted by Paze View Post
    Say 4 men lift 200 kilos. Can I simply divide 200 by 4 to get 50kg each...So they lifted 50kilos each (given the same posture and dimensions of the lift)?

    Or is the calculation more complex?
    50 kg is the average weight lifted. If add the assumption that they all lifted the same weight, then you can say they each lifted 50 kg.
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  3. #3
    MHF Contributor ebaines's Avatar
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    Re: Dividing mass lifted by parties

    If the four men are evenly spaced around the edge of the object and if the center of gravity of the object is precisley in the middle (and hence equi-distant from all four men) then the 50 Kg/person calculation should be pretty accurate. But in the real world it often doesn't work out quite so ebevenly. Most objects are odd-shaped, so the center-of-gravity is not precisely in the middle. Plus it's possible that two men on opposite corners may do more lifting than the those on the other two corners. For example, it's quite possible for two men on opposite corners to lift 80 Kg each while the other two are lifting only 20 Kg each.
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  4. #4
    Senior Member Paze's Avatar
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    Re: Dividing mass lifted by parties

    Thanks for verifying, guys!

    For anyone who's wondering, I was doing some physics calculations on the blockbuster "Pacific Rim". I was wondering whether the choppers could hold the Jaegers (they can't)
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