# Dividing mass lifted by parties

• Aug 18th 2013, 01:20 PM
Paze
Dividing mass lifted by parties
Say 4 men lift 200 kilos. Can I simply divide 200 by 4 to get 50kg each...So they lifted 50kilos each (given the same posture and dimensions of the lift)?

Or is the calculation more complex?
• Aug 18th 2013, 01:30 PM
HallsofIvy
Re: Dividing mass lifted by parties
Quote:

Originally Posted by Paze
Say 4 men lift 200 kilos. Can I simply divide 200 by 4 to get 50kg each...So they lifted 50kilos each (given the same posture and dimensions of the lift)?

Or is the calculation more complex?

50 kg is the average weight lifted. If add the assumption that they all lifted the same weight, then you can say they each lifted 50 kg.
• Aug 19th 2013, 11:22 AM
ebaines
Re: Dividing mass lifted by parties
If the four men are evenly spaced around the edge of the object and if the center of gravity of the object is precisley in the middle (and hence equi-distant from all four men) then the 50 Kg/person calculation should be pretty accurate. But in the real world it often doesn't work out quite so ebevenly. Most objects are odd-shaped, so the center-of-gravity is not precisely in the middle. Plus it's possible that two men on opposite corners may do more lifting than the those on the other two corners. For example, it's quite possible for two men on opposite corners to lift 80 Kg each while the other two are lifting only 20 Kg each.
• Aug 20th 2013, 12:16 AM
Paze
Re: Dividing mass lifted by parties
Thanks for verifying, guys!

For anyone who's wondering, I was doing some physics calculations on the blockbuster "Pacific Rim". I was wondering whether the choppers could hold the Jaegers (they can't) :)