# This as been sending me round the bend

• Aug 18th 2013, 01:14 PM
fatherjack
This as been sending me round the bend
How long does each node transmit for in every hour? Express your answer in seconds.

33 ms = 33 x 10-3 s = 0.033 s
So, the duty cycle is (0.033 s ÷ T s) x 100% = 3%
Transposing the formula gives T s =

1 hour : 60 *60= 3 600
• Aug 18th 2013, 01:23 PM
Paze
Re: This as been sending me round the bend
You need to clarify your problem better. The one before this is utter gibberish...Excuse me if I am wrong but I can't make no sense of your questions.
• Aug 18th 2013, 01:28 PM
HallsofIvy
Re: This as been sending me round the bend
Quote:

Originally Posted by fatherjack
How long does each node transmit for in every hour? Express your answer in seconds.

33 ms = 33 x 10-3 s = 0.033 s
So, the duty cycle is (0.033 s ÷ T s) x 100% = 3%
Transposing the formula gives T s =

So you are saying $\frac{.033}{T}= .03$?
Multiplying both sides by T, .033= .03T
Dividing both sides by .03, $T= \frac{.033}{.3}= \frac{33}{30}= 1.1$

Quote:

1 hour : 60 *60= 3 600

• Aug 18th 2013, 02:31 PM
fatherjack
Re: This as been sending me round the bend
sorry for not making it clear I need to find the value of T to solve equation but as it represents part of the duty cycle
• Aug 19th 2013, 12:42 PM
fatherjack
Re: This as been sending me round the bend
thank you for your help but how do I work out how mant times the node transmits for