Results 1 to 4 of 4

Math Help - Making sense of it all

  1. #1
    Newbie
    Joined
    Nov 2012
    From
    United Kingdom
    Posts
    19

    Making sense of it all

    33 ms = 33 x 10-3 s = 0.033 s
    So, the duty cycle is (0.033 s T s) x 100% = 3%
    (what is the value of T)

    Transposing the formula gives T s = insert your workings here =


    = Ans A s
    = Ans B ms
    1 hour = 60min x 60 s = 3 600 s


    So, in 1 hour the node transmits,
    3 600 s = Ans C times
    Ans A s


    Therefore, node transmits for

    0.033 s x Ans C =

    = Solution (3 s.f.) in every hour
    Last edited by fatherjack; August 18th 2013 at 12:52 AM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Sep 2012
    From
    Australia
    Posts
    3,648
    Thanks
    601

    Re: Making sense of it all

    Hey fatherjack.

    Did you have a specific question in mind? Are you trying to understand a general concept better?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Nov 2012
    From
    United Kingdom
    Posts
    19

    Re: Making sense of it all

    hi thanks for getting back to me
    well a bit of both really, I want to work out the value of T?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    Nov 2012
    From
    United Kingdom
    Posts
    19

    Re: Making sense of it all

    20 ms in every 0 Calculate the duty cycle of a device that typically connects to a network and transmits for.5 s. You may wish to use a calculator for this activity.
    20 ms = 20 10−3 s = 0.02 s
    So the duty cycle is (0.02 0.5) 100% = 4%
    This means that the device is operational for only 4% of the time. This is a example
    --------------------------------------------------------------------------------------------------------------------------------------------

    I need to work out the value of T



    A typical sensor node has a transmit duty cycle of 3% and draws a current of 1.53 mA while it is in the active part of the duty cycle, and negligible current while in the inactive part of the duty cycle. On average, the node sends 375 bits of data per transmission and each transmission takes 33.0 ms.
    i. How long does each node transmit for in every hour? Express your answer in seconds.

    33 ms = 33 x 10-3 s = 0.033 s
    So, the duty cycle is (0.033 s T s) x 100% = 3%
    Transposing the formula gives T s =
    = Ans A s
    = Ans B ms
    1 hour = 60min x 60 s = 3 600 s
    So, in 1 hour the node transmits,
    3 600 s = Ans C times
    Ans A s


    Therefore, node transmits for

    0.033 s x Ans C =

    = Solution (3 s.f.) in every hour
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 0
    Last Post: November 16th 2011, 01:16 AM
  2. Does this make sense?
    Posted in the Calculus Forum
    Replies: 2
    Last Post: April 4th 2011, 02:20 PM
  3. Geo HW not AT ALL making sense
    Posted in the Geometry Forum
    Replies: 7
    Last Post: December 7th 2008, 07:18 PM
  4. Not making sense...probability
    Posted in the Advanced Statistics Forum
    Replies: 3
    Last Post: October 13th 2008, 04:54 PM
  5. Does this make sense?
    Posted in the Advanced Statistics Forum
    Replies: 0
    Last Post: May 5th 2008, 08:17 PM

Search Tags


/mathhelpforum @mathhelpforum