can anyone simplify this for me or possibly run me through how to simplify it?

4x + 2 / x² + 4x + 3 * x + 3 / 7x + 5

Thank you

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- Nov 6th 2007, 03:57 AMajwatson88simplifing algebraic fractions
can anyone simplify this for me or possibly run me through how to simplify it?

4x + 2 / x² + 4x + 3 * x + 3 / 7x + 5

Thank you - Nov 6th 2007, 04:05 AMtopsquark
Is this supposed to be

$\displaystyle \frac{4x + 2}{x^2 + 4x + 3} \cdot \frac{x + 3}{7x + 5}$?

Then the above is equal to:

$\displaystyle = \frac{2(2x + 1)}{(x + 1)(x + 3)} \cdot \frac{x + 3}{7x + 5}$

Notice the common x + 3 in the numerator and denominator. So....

$\displaystyle = \frac{2(2x + 1)}{x + 1} \cdot \frac{1}{7x + 5}$

$\displaystyle = \frac{2(2x + 1)}{(x + 1)(7x + 5)}$

-Dan - Nov 6th 2007, 04:05 AMkalagota
- Nov 6th 2007, 04:13 AMtopsquark
- Nov 6th 2007, 04:14 AMajwatson88another question
im not entily sure how to group the expressions but ill give it a go.

could anyone help me with this as well

__3_____ .__2x + 4__

x + 2 x

thanks again - Nov 6th 2007, 05:06 AMtopsquark
As with the last example, start by factoring:

$\displaystyle \frac{3}{x + 2} \cdot \frac{2x + 4}{x} = \frac{3}{x + 2} \cdot \frac{2(x + 2)}{x}$

As for how to write it, what we were referring to was writing your expressions something like this:

3/(x + 2) times (2x + 4)/x

as opposed to

3/x + 2 times 2x + 4/x

which is confusing.

-Dan