Hi guys, What are the real solutions, in any, of log(x) = 2log(3) + log(5) - log(2) - 1 (all logs are to base 10) Thanks in advance for help.
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Originally Posted by Coshy Hi guys, What are the real solutions, in any, of log(x) = 2log(3) + log(5) - log(2) - 1 (all logs are to base 10) Thanks in advance for help. where is the base for the logarithms, so .
IF you know the "laws of logarithms": a log(b)= log(b^a) and log(a)+ log(b)= log(ab), this problem is easy. If you do NOT the you should not be attempting a problem like this.
Originally Posted by ibdutt You are assuming that an unqualified denotes which might be the case in high school maths classes but is not in the wider world. .
Originally Posted by Coshy What are the real solutions, in any, of log(x) = 2log(3) + log(5) - log(2) - 1 (all logs are to base 10) Originally Posted by zzephod You are assuming that an unqualified denotes which might be the case in high school maths classes but is not in the wider world.. The OP clearly states they are indeed base 10. Please read the entire thread before positing.
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