$\displaystyle \sqrt{\frac{18ab}{16b^4}} = \sqrt{\frac{9a}{8b^3}}$ Is that in simplest form? There is probably something else I can do but I can't spot anything
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Originally Posted by uperkurk $\displaystyle \sqrt{\frac{18ab}{16b^4}} = \sqrt{\frac{9a}{8b^3}}$ Is that in simplest form? There is probably something else I can do but I can't spot anything It really depends upon you mean by simplest form. You can say $\displaystyle \sqrt{\frac{18ab}{16b^4}} = \sqrt{\frac{9a}{8b^3}}=\frac{3}{2}\sqrt{\frac{a}{2 b}}$ .
Originally Posted by Plato It really depends upon you mean by simplest form. You can say $\displaystyle \sqrt{\frac{18ab}{16b^4}} = \sqrt{\frac{9a}{8b^3}}=\frac{3}{2}\sqrt{\frac{a}{2 b}}$ . But would that be classed as "simpler" or just equally similar? Write in simplest radical form: $\displaystyle \sqrt[3]{54y^8}$ and I have no idea how to go about this. **EDIT** $\displaystyle \sqrt{(6y\times9y)^4}$ is this a start?
Last edited by uperkurk; Aug 7th 2013 at 11:55 AM.
Originally Posted by uperkurk But would that be classed as "simpler" or just equally similar? Well, I did say it depends on who is asking. Originally Posted by uperkurk Write in simplest radical form: $\displaystyle \sqrt[3]{54y^8}$ and I have no idea how to go about this. $\displaystyle \sqrt[3]{54y^8}=\sqrt[3]{(7)(2^3)(y^6)(y^2)}}=2y^2\sqrt[3]{7y^2}$
Originally Posted by Plato Well, I did say it depends on who is asking. $\displaystyle \sqrt[3]{54y^8}=\sqrt[3]{(7)(2^3)(y^6)(y^2)}}=2y^2\sqrt[3]{7y^2}$ I was actually asking you, in your opinion, which would you prefer to see? also did you mean $\displaystyle \sqrt[3]{(6)(3^3)(y^6)(y^2)}$ ? Also I can see how you worked it out, thanks.
Last edited by uperkurk; Aug 7th 2013 at 12:02 PM.
Originally Posted by Plato Well, I did say it depends on who is asking. $\displaystyle \sqrt[3]{54y^8}=\sqrt[3]{(7)(2^3)(y^6)(y^2)}}=2y^2\sqrt[3]{7y^2}$ hello, I don't want to pick at and you but... $\displaystyle 7 \cdot 8 \ne 54$
Originally Posted by uperkurk I was actually asking you, in your opinion, which would you prefer to see? also did you mean $\displaystyle \sqrt[3]{(6)(3^3)(y^6)(y^2)}$ ? Also I can see how you worked it out, thanks. ... probably you mean: $\displaystyle \sqrt[3]{(2)(3^3)(y^6)(y^2)}$
Originally Posted by earboth ... probably you mean: $\displaystyle \sqrt[3]{(2)(3^3)(y^6)(y^2)}$ wha?!!! now I'm mega confused... $\displaystyle (2)(9)=18$ $\displaystyle (6)(9)=54$ ?
Originally Posted by earboth hello, I don't want to pick at and you but... $\displaystyle 7 \cdot 8 \ne 54$ I don't know what I was thinking. Of course it is 56. But $\displaystyle 54=2(3^3)$ so $\displaystyle \sqrt[3]{54}=3\sqrt[3]2$
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