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Math Help - fractions again

  1. #1
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    fractions again

    \left\frac{1}{x}+\frac{1}{3}=\right\frac{3}{2x}-1

    So the lowest common multiple is 6? As they both already have an x in them. So... 6\times\left(\frac{1}{x}+\frac{1}{3}\right)=\left(  \frac{3}{2x}-1\right)\times6

    So then I have \frac{6}{6x}+2=\frac{18}{12x}-6

    x+2=\frac{3}{2x}-6

    is this correct so far? What next?
    Last edited by uperkurk; July 31st 2013 at 07:54 AM.
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    Re: fractions again

    Nevermind I saw what I did wrong... fractions is stupidly difficult, so much messing around is needed to simple add or subtract a damn fraction...
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    Re: fractions again

    Don't worry about it. There are any number of students out there who have a hard time with fractions. It seems to be a concept that is difficult to learn.

    Why don't you post your solution? That way someone who is also having troubles can take a look at it.

    -Dan
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    Re: fractions again

    Quote Originally Posted by topsquark View Post
    Don't worry about it. There are any number of students out there who have a hard time with fractions. It seems to be a concept that is difficult to learn.

    Why don't you post your solution? That way someone who is also having troubles can take a look at it.

    -Dan
    It just takes me longer than most people to spot the "obvious" and sometimes I just get a complete mind blank and it's very frustrating. I even forget the most basic of things like 2 is the same thing as \frac{2}{1}

    anyway, my solution:

    \frac{1}{x}+\frac{1}{3} = \frac{3}{2x}-1

    6x\times\left(\frac{1}{x}+\frac{1}{3}\right)=\left  (\frac{3}{2x}-1\right)\times6x

    \frac{6x}{x}+2x=\frac{18x}{2x}-6x

    after cancellation:

    6+2x=9-6x

    6-9=-6x-2x

    8x=3

    x=\frac{3}{8}

    This is what it's like for every question I have like this, I need to write down all the steps otherwise I just lose track of what is what, very annoying
    Last edited by uperkurk; July 31st 2013 at 11:42 AM.
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    Forum Admin topsquark's Avatar
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    Re: fractions again

    Quote Originally Posted by uperkurk View Post
    This is what it's like for every question I have like this, I need to write down all the steps otherwise I just lose track of what is what, very annoying
    That's pretty much how everyone has to learn this stuff. You're doing good.

    -Dan
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