I am unable to find the answer of this question. Any help will be appreciated
If A^2 + B^2 =1 then find the range of (a+b) where a and b is real.
Last edited by varunkanpur; Jul 30th 2013 at 03:03 AM.
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Are you aware that the graph of is a circle with center at (0, 0) and radius 1? So that the circle extends from x= -1 to x= 1 horizontally, and y= -1 to 1 vertically.
Originally Posted by varunkanpur I am unable to find the answer of this question. Any help will be appreciated
If A^2 + B^2 =1 then find the range of (a+b) where a and b is real. Technical point: a and A are not the same variable.
Assuming you haven't done geometry of the circle you can think of it this way.
Think of the maximum and minimum vales of B so that A is real. Then do the same thing for A instead of B.
hmm if you've done trigonometry,try this. Let A=sin x and B=cos x[Parametric equation of circle]. Now range of A+B is Range of sin x + cos x i.e [-1/sqrt(2),1/sqrt(2)].
Last edited by smatik; Aug 2nd 2013 at 09:51 PM.
smatak has a good idea, but unfortunately he gave the wrong answer.
So the range of sin(x)+cos(x) is
oh yea.i calculated wrong.... btw its smatik
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