little help with simple word problems

Hi guys,

I'm a 2nd year university student majoring in Criminology and a minor in Psychology at Simon Fraser University in the Vancouver BC area. that being said; i'm a fail with numbers...

Getting to the point: I have an aptitude test for the Canadian Armed Forces and while reviewing the practice exam I had come across several word problems that I need help fully understanding. I will post them below ( I copied them straight from the practice exam, and the **bolded **answers is the correct one)

4. If in the army there is one officer for every 16 privates, how many officers are

there in a regiment consisting of 1,105 officers and privates?

(A) 62 **(B) 65** (C) 67 (D) 69

10. How many soldiers are there in a group of 27 sailors and soldiers if there

are four fifths as many sailors as soldiers?

(A) 6 **(B) 15** (C) 21 (D) 22

I need help understanding how the answers came to be.

Thanks so much , and if any of you are from the Vancouver BC area we could meet up for a beer ! http://cdn.mathhelpforum.com/images/icons/icon12.png

PS i posted in the algebra section because i'd figured the word problems require simple algebra in order to be solved.

Re: little help with simple word problems

For 16 privates we have 1 officer

for 16x2 privates we have 2 officers

for 16x3 privates we have 3 officers

in general for 16 x n privates n officers and total strength of officers and privates = 16 n + n = 17 n which in this case is given to be 1105 thus n = 1105/17 = 65

hence we have 65 officers

Re: little help with simple word problems

For 10.

let the number of soldiers be x then the number of soldiers = 4/5 x

total soldiers and sailors = x + 4/5 x = 9/5 x which in this case is given to be 27.

now you can solve it further

Re: little help with simple word problems

for the first problem; where did you get 17

for the second problem; where did you get 9/5

Re: little help with simple word problems

First: 16 n + 1 n = 17 n

Second one

x + 4/5 x = (9/5 ) x