# Thread: boxes of candy bars

1. ## boxes of candy bars

A club is buying boxes of candy bars to sell for a fundraiser. If each box contains c candy bars, and each member sells x bars a day, how many boxes are needed to supply enough candy bars for 3c members to sell for 5 days?

A) 15c(^2) x
B) x/15
C) (3x)/5
D) (15c2)/x
E) 15x

I have no concept how to do this. I tried to plug in, by assuming c=200, and x=2. So 200 bars were sold in 100 days by one member. And now i'm at a loss with what to do....Answer is 15x (E)

2. ## Re: boxes of candy bars

Originally Posted by usre123
A club is buying boxes of candy bars to sell for a fundraiser. If each box contains c candy bars, and each member sells x bars a day, how many boxes are needed to supply enough candy bars for 3c members to sell for 5 days?

A) 15c(^2) x
B) x/15
C) (3x)/5
D) (15c2)/x
E) 15x

I have no concept how to do this. I tried to plug in, by assuming c=200, and x=2. So 200 bars were sold in 100 days by one member. And now i'm at a loss with what to do....Answer is 15x (E)
Well:
1 member sells x bars in 1 day, so
3c members will sell y bars in 5 days

You can find y with that.
And y is the number of bars needed to supply the 3c members for the 5 days.
After you find the number(y) of bars needed, you can find how many boxes you will need to supply them, since you know that 1 box contains c bars.

3. ## Re: boxes of candy bars

Thank you. I got the answer
1 member sells x candy bars n a day. so I say x=2. And c=200.
3*200= 600. How many boxes needed for 600 members for 5 days. Each member sells 2 a day.So each member will sell 10 in 5 days.
600*10= 6000. Thats 6000 candy bars I need.
Each box contains 200 bars. For 6000 bars I need 6000/200 boxes, which is 30.
Since E is 15x, thats 15 *2 =30.