So y= cos(2(x- 45)). This problem looks like it expects you to know how to work with a "general sinusoidal function". Since cosine of any number lies between -1 and 1, this function will always lie between -2 and 2. Cosine has period degrees but when , so this function has period degrees. Finally, cos(0)= 1 and 2x- 90= 2(x- 45)= 0 when x= 45.

So I would do this: Draw two horizontal lines at y= -2 and y= 2 to give the boundaries. Start at the upper line at x= 45. 45+ 180= 225 so mark (225, 2). The 180 interval divides into 4 sections: 180/4= 45 so at x= 45+ 45= 90, we are at 0, at 90+ 45= 135 down to -2, at 135+ 45= 180, up to 0 again, at 180+ 45= 225 up to 2 again, completing the cycle.